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Tag: Calculus

Differentials and Linear Approximation

by theorangedog on Jan.11, 2008, under Skills

Q. Find the linear change in volume dV if the sides of a cube change from 10 to 10.1.

A. We can use the definition of small dy = (dy/dx)dx to determine the estimated linear change. In this problem, we start with the cubic volume equation of small V = x^3 where small x is the length of one side of the cube. The derivative is then small f^{prime}(V) = 3x^2. Filling in for linear approximation we get small dV = 3x^2dx. This results in small dV = 3(10^2)(.1) = 30. We can see that the linear approximation is not entirely accurate, hence the name approximation, as small Delta V = 10.1^3 - 10^3 = 30.301.

Related equations and relationships:
If small df/dx > 0 then small f(x) is increasing. If small df/dx < 0 then small f(x) is decreasing.

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Derivative Rules in Basic Calculus

by theorangedog on Jan.03, 2008, under Skills

Rule of Linearity
small (au + bv)^prime = au^prime + bv^prime
Product Rule
small (uv)^prime = uv^prime + vu^prime
Reciprocal Rule
small (1/v)^prime = -v^prime/v^2
Quotient Rule
small (u/v)^prime = (vu^prime - uv^prime)/v^2
Power Rule
small (u^n)^prime = nu^{n-1}u^prime

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Welcome Back To Calculus

by theorangedog on Jan.02, 2008, under Skills

Problem:
A rock thrown upward with velocity 16 ft/sec reaches height small f = 16t - 16t^2 at time t.
(a) Find its average speed smallDelta f/Delta t from small t = 0 to small t = frac{1}{2}.
(b) Find its average speed smallDelta f/Delta t from small t = frac{1}{2} to small t = 1.
(c) What is small df/dt at small t = frac{1}{2}?

Solution:
To find speed given distance, we need to take the first derivative. Derivatives of polynomials are one of the few things I remember, even though this is covered in the material I’m reading. That equation is: small f^prime (t) = 16 - 32t. However, the question isn’t asking for a limit, so the full equation of smallfrac{Delta f}{Delta t} = frac{f(t+Delta t) - f(t)}{Delta t} should be used. Essentially, it is the average of the first derivative at two given points.
This results in:
(a) 8 ft/sec
(b) -8 ft/sec
(c) 0, as it is the instantaneous point of reversal (this one assumes a limit, as t approaches smallfrac{1}{2})

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